Thanks Steve- That was it.
I had tried this first, and when it didn't work I went on to other dead ends.  Looking 
at my first try, I see that I had a mis-placed > in my [<@CURROW,5>] syntax.  
Time to set this aside and enjoy the weekend.
Thanks again-
Mark Bushaw

On 15 Jun 2002 at 20:21, Steve Smith wrote:

> Try <@ASSIGN NAME='variablename[<@CURROW>,5]'
> VALUE='http://www@@variablename[<@CURROW>,5]'> inside of a <@ROWS
> ARRAY=variablename></@ROWS> loop.
> 
> I haven't tested this so you might want to check the syntax.
> 
> Hope this helps,
> 
> Steve Smith
> 
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> 
> -----Original Message-----
> From: [EMAIL PROTECTED]
> [mailto:[EMAIL PROTECTED]]On Behalf Of Mark Bushaw
> Sent: June 15, 2002 7:31 PM
> To: Multiple recipients of list witango-talk
> Subject: Witango-Talk: Modifying contents of an Array
> 
> 
> I guess my brain is on strike, because I can't figure this out-
> I perform a search and assign the results to an array.  Then I want to
> modify the
> contents of one column in every row (modify the item number to a full URL),
> then
> perform formatting and save as a .txt file.
> I've got everything except the cell modification.  I can't figure out the
> syntax for
> making the <@REPLACE> to work.  In my example I need to modify the 5th
> column of every row by adding http://www... to the beginning of the existing
> data
> (productID).  I can read the column, add the URL data and see the correct
> results
> as a separate variable (so I know that part is OK), but I can't figure out
> how to get
> that back into the array.
> I'm thinking I may have to create a new array, and load it with the data
> from the
> resultset plus the modified data, but thought I'd check to see if there was
> an easier
> way.
> Thanks
> Mark Bushaw
> 
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