I have a form that starts with choosing a category and a subcategory.
The categories and subcategories are read from a mysql database using a
PHP script.
When New is chosen from Category I want the Category chose to change
from a select to a text input box for both the Category and Subcategory
fields.
When new is chosen in subcategory and want the form field for
subcategory alone to change to a text input box.
I can get the subcategory boxed changed. I can't get the javascript to
have the PHP change both the category and subcategory at the same time.
It appears to only allow me to change the contents of one <td> area on
the form not two. (Yes I know we shouldn't be using td for this but it
is a legacy FP site I just took over. Just figuring out how to use PHP
with FP was fun)
Essentially the relevent html code is this
form action="process.php" method="post">
<table>
<? if ($ERRORS=="Y") echo
"<tr><td>There are errors on the page.</td><td>All errors marked in
red.</td></tr><tr><td></td></tr>";?>
<tr><td>Required fields
marked with *</td></tr>
<tr>
<td>Category*:</td>
<td><div
id="cat"><select name="category" onchange="showSubcategory(this.value)">
<option VALUE =
"selected"> SELECT</option>
<option
value="NEW">NEW</option>
<?$myrow =
mysql_fetch_array($result);
echo "<option value="
.$myrow['category'];
echo ">".
$myrow['category']. "</option>";
if ($myrow =
mysql_fetch_array($result)) {
// display list
do {
echo "<option
value=" .$myrow['category']. ">". $myrow['category']. "</option>";
} while ($myrow =
mysql_fetch_array($result));
} else {
// no records to display
echo "Sorry, no
records were found!";
}
?>
</select>
</div></td>
</tr>
<tr>
<td>Subcategory*:</td>
<td><div id="txtHint">
<select
name='subcategory' onchange="showSubcategory2(this.value)">
<option VALUE =
"selected"> SELECT</option>
<option
VALUE="NEW">NEW</option>
</select>
</div></td>
</tr>
The java script is here
var xmlHttp
function showSubcategory(str)
{
xmlHttp=GetXmlHttpObject()
if (xmlHttp==null)
{
alert ("Browser does not support HTTP Request")
return
}
var url="getsubcategory.php"
url=url+"?q="+str
url=url+"&sid="+Math.random()
xmlHttp.onreadystatechange=stateChanged
xmlHttp.open("GET",url,true)
xmlHttp.send(null)
}
function stateChanged()
{
if (xmlHttp.readyState==4 || xmlHttp.readyState=="complete")
{
document.getElementById("txtHint").innerHTML=xmlHttp.responseText
}
}
function GetXmlHttpObject()
{
var xmlHttp=null;
try
{
// Firefox, Opera 8.0+, Safari
xmlHttp=new XMLHttpRequest();
}
catch (e)
{
//Internet Explorer
try
{
xmlHttp=new ActiveXObject("Msxml2.XMLHTTP");
}
catch (e)
{
xmlHttp=new ActiveXObject("Microsoft.XMLHTTP");
}
}
return xmlHttp;
}
I'm sure this is real easy but javascript is my new toy. I promise to
try and be helpful to people on PHP problems.
--
Michael Horowitz
Your Computer Consultant
http://yourcomputerconsultant.com
561-394-9079
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