Now firebug gives the error
showSubcategory2(document.getElementById(
Code is
Code samples I've been able to review
<select name="subcategory" id = "subcategory"
onchange="showSubcategory2(document.getElementById('category').value,this.options[this.selectedIndex].value);">
I know this will be simple at the end.
Michael Horowitz
Your Computer Consultant
http://yourcomputerconsultant.com
561-394-9079
Brian Cummiskey wrote:
Michael Horowitz wrote:
<select name="subcategory" id = "subcategory"
onchange="showSubcategory2(document.getElementById('category').value,document.getElementById('subcategory').value)">
try this:
<select name="subcategory" id="subcategory"
onchange="showSubcategory2(document.getElementById("category").value,
this.options[this.selectedIndex].value);">
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