Now firebug gives the error
showSubcategory2(document.getElementById(

Code is


Code samples  I've been able to review

<select name="subcategory" id = "subcategory" 
onchange="showSubcategory2(document.getElementById('category').value,this.options[this.selectedIndex].value);">



I know this will be simple at the end.

Michael Horowitz
Your Computer Consultant
http://yourcomputerconsultant.com
561-394-9079



Brian Cummiskey wrote:
Michael Horowitz wrote:
<select name="subcategory" id = "subcategory" onchange="showSubcategory2(document.getElementById('category').value,document.getElementById('subcategory').value)">


try this:

<select name="subcategory" id="subcategory" onchange="showSubcategory2(document.getElementById("category").value, this.options[this.selectedIndex].value);">



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