Thnaks to Joe K1JT that directed me to the right answer https://wsjt.sourceforge.io/FT8_DXpedition_Mode.pdf page9
If you are using N Slots signals, your average transmitted power will be P0/(N Slots) and the power in each signal will be P0/(N Slots) 2. Thus, for N Slots = 1, 2, 3, 4, and 5 the average power per signal will be down from P0 by about 0, 6, 9.5, 12, and 14 dB, respectively. On Sat, Jan 7, 2023 at 2:28 PM José Nunes CT1BOH <ct1...@gmail.com> wrote: > I wonder if anyone can confirm this?! > > In FT8 if I copy a DX station TX, with only one stream, at -10dB: > > - If the station goes F/H with two streams, then the signal of each of > the two streams goes down to -13,01 dB because the energy of one stream is > split by half > - If the station goes F/H with three streams, then the signal of each > of the three streams goes down to -14.77 dB because the energy of one > stream is split by three > > Are the two sentences above correct? > > -- > José Nunes > CONTEST CT1BOH - http://www.qsl.net/ct1boh > -- José Nunes CONTEST CT1BOH - http://www.qsl.net/ct1boh
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