Neeraj is correct. Even though our tools push you to use one webContent folder, a user could modify their component to use multiple, so you can't assume there is only one.
To get all, you can call component.getRootFolder().getUnderlyingFolders().
Hope that helps,
John Lanuti
Software Engineer, IBM Rational
[EMAIL PROTECTED]
t/l 441-7861
"I know this lady way down in my country.
She is so pretty that my eyes throw disguises at me.
Now we will sit and we'll wonder about our future,
But now I'm thinking that today sounds fine to me." - Of A Revolution
| Neeraj Agrawal/New Haven/[EMAIL PROTECTED]
Sent by: [EMAIL PROTECTED] 04/07/2006 02:18 PM
|
|
You can use following :
IVirtualComponent component = ComponentCore.createComponent( project );
component.getRootFolder().getProjectRelativePath();
But... component.getRootFolder().getProjectRelativePath() gives the first folder which is mapped to deploy-path of "/" .
In the default web project created by WTP , it is the WebContent, so you will get it back
<wb-resource source-path="/WebContent" deploy-path="/"/>
Thanks
Neeraj Agrawal
| "Ian Trimble"
<[EMAIL PROTECTED]> Sent by: [EMAIL PROTECTED] 04/07/2006 02:02 PM
|
|
Hi,
For the JSF Tools Project, we have situations where we need to obtain an IPath for the "WebContent" (regardless of actual name that user specifies) folder. We have discovered at least one approach (get WebArtifactEdit, get its deployment descriptor path, strip a couple of segments from it), but now I am wondering if there is an approach that feels like less of a hack.
Is there a recommended (and robust, of course) approach that anyone is willing to recommend (taking into consideration the fact that we cannot assume a constant name of "WebContent", since the user can change this)?
Thanks in advance,
- Ian
------------------------------------------------------------
Ian Trimble
JDeveloper Group
Oracle Corporation Canada Inc.
Office: (250) 954-0837
Email: [EMAIL PROTECTED]
Web: http://www.oracle.com
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