You are several ways to do this depending on your particular needs, here's one, add your data directory to your load path in the script you're using:
$LOAD_PATH.unshift File.join(File.dirname(__FILE__),'..','data')
This assumes your data directory is one up from the file you're trying to access it from, change it if you're looking for something else, but this should give you the basic idea.
-Charley
On 8/5/06, VIKASH KUMAR <[EMAIL PROTECTED]> wrote:
I am loading a file by giving the absolute path, the below code works fine:excel = WIN32OLE::new('excel.Application')
workbook = excel.Workbooks.Open ('C:\demo\mation.xls')
worksheet = workbook.Worksheets(1)
worksheet.Select
excel['Visible'] = trueI want to use the name of the file to open ' mation.xls', not the entire path 'C:\demo\mation.xls'.Please send me a solution for this.Thanks in advanceVikash Kumar
Here's a new way to find what you're looking for - Yahoo! Answers
_______________________________________________
Wtr-general mailing list
[email protected]
http://rubyforge.org/mailman/listinfo/wtr-general
_______________________________________________ Wtr-general mailing list [email protected] http://rubyforge.org/mailman/listinfo/wtr-general
