Here's one way to do it:
row_values = row.text.split(/\w+ /)
1.upto (row_values.length) do |number|
puts "date#{number} = #{row_value[number - 1]}, month#{number}=
#{row_value[number - 1]}, Year#{number}= #{row_value[number -
1]}, value#{number} = #{row_value[number - 1]}, Status#{number} =
#{row_value[number - 1]}
split divides a string where it encounters it's argument and returns an
array of the elements of the string left over. I could have put a space " "
inside the parentheses for split, but I couldn't see whether you had more
than one space in that list of values. So I used a regular expression /\w+/
instead, which means "any whitespace at all, including tabs and newlines and
such".
Then we just count. We need to know the number of elements in the array, so
we use "length". You wanted your text to start counting at one, but arrays
are indexed by zero, so I have to slice the array with "number-1" for each
time through the loop.
BTW, this is a classic associative array, also known as a hash. A hash
might be a better way to arrange this information. You could search google
for "ruby array" and "ruby hash" for more information.
On 1/15/07, VIKASH KUMAR <[EMAIL PROTECTED]> wrote:
I am running a test case, in which I want to store all the values of a
table in variables, I am using the below code:
require 'watir'
ie=Watir::IE.start("C:\test.htm")
class Test
def test_row_collection(ie)
t= ie.table(:class,'listView')
value_i = 0
t.rows.each do |row|
puts row
puts "Our Number is " && value_i
value_i += 1
end
end
end
TestObj = Test.new
TestObj.test_row_collection(ie)
It displays the following output:
type:
id:
name:
value:
disabled: false
0
type:
id:
name:
value:
disabled: false
1
type:
id:
name:
value:
disabled: false
If I used "puts row.text" in the above definition, it displays the
following output.
0
01/14/2007 Jan/2007 2007 13 Open
1
01/15/2007 Jan/2007 2007 16 Open
I want to store values like this:
date1 = 01/14/2007, month1= Jan/2007, Year1= 2007, value1 = 13, Status1 =
Open
date2 = 01/14/2007, month2= Jan/2007, Year2= 2007, value2 = 16, Status2 =
Open
Please help me out in doing this.
Thanks in advance
Vikash
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