Hello, X10 users I am writing this post about the question that is related to the the size of EXE file based on the C++ backend.
When it comes to compiling *.x10 source code, I would like to know the difference between one and two steps. In other words, due to some reasons, I am using the two-step-compile way: (1) compile *.x10 to *.cc, then (2) *.cc to binary. When I use the two-step-compile, the final executable binary file size is bigger than the one-step-compile -- compiling *.x10 to binary. Specifically, it would be about 3 times as bigger as the one by the one step compile way. As my observation of the compile, it seemed to me that it took longer time to generate the procedure of the final executable, rather than dealing with object files (*.o). It would be helpful if you give me some comments or advice. ----------------------------------------------------------------------- Here are my system environment informations: ----------------------------------------------------------------------- $ OS: Linux 2.6.32-26-generic-Ubuntu $ x10c++ version: 2.1.1 $ g++ --version: g++ (Ubuntu 4.4.3-4ubuntu5) 4.4.3 $ javac -version: javac 1.6.0_20 $ java -version: java version "1.6.0_20" $ mpicxx --version: c++ (Ubuntu 4.4.3-4ubuntu5) 4.4.3 ----------------------------------------------------------------------- Attached is my Makefile, in which I used "make postmpicxx". Best regards, Myoungkyu Song
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