Hello again,
So, I used the ateach statement and now I can fill the distributed array
with my objects.
BUT, I cannot access them.
I tried the result() function of ArrayBuilder and just tried to print it
with :
Console.OUT.println(results(p).result())
I get the reference of the object in the heap, but I cannot use the
functions of my class (Tup) on it.
So
results(p).result().myfunct()
does not compile.
So, is there any other function apart from result() that would do the work?
Cheers
2013/6/6 Konstantina Panagiotopoulou <kwno...@hotmail.com>
> Hello all,
>
> I am new to x10 and currently I trying to develop a parallel version of
> my program with a DistArray
>
> So, I need to store objects of my own class "Tup" (instead of primitive
> types) in the distributed array.
>
> I tried to follow the code I found here:
>
> http://sourceforge.net/mailarchive/forum.php?thread_name=CADmVTxxhj%2B29GRR2XF9aw9e7hA3AdSc8_ksA-aLsOAgFS9FaYQ%40mail.gmail.com&forum_name=x10-user<http://sourceforge.net/mailarchive/forum.php?thread_name=CADmVTxxhj%2B29GRR2XF9aw9e7hA3AdSc8_ksA-aLsOAgFS9FaYQ%40mail.gmail.com&forum_name=x10-users>
>
> and I 've got the following inside the caller - class
>
> public var dimx: Int ;
> public var R:Region(1);
> public val D:Dist;
> public var results: DistArray[ArrayBuilder[Tup]](D);
>
>
> public def this(dimx: Int){
>
> this.dimx = dimx;
> this.R = 1..dimx;
> this.D = Dist.makeBlock(R);
>
> this.results = DistArray.make[ArrayBuilder[Tup]](D);
> }
>
> Till here it compiles ok, but then I try to populate the array...
>
> public def fill(results:DistArray[ArrayBuilder[Tup]]){
> finish for( p in results.dist.places()) {
> at (p) async {
> results(here.id)=new ArrayBuilder[Tup]();
> }
> }
>
> finish for( p in Place.places()){
> at (p) async {
> results(here.id).add(new Tup(2, 6));
> //processing the strings in Read(here.id);
> }
> }
> }
>
> And get an error:
>
>
> x10:59: Generated a dynamic check for the method call.
>
> So, my question is, how I can access my objects through the ArrayBuilder
> in the DistArray.
>
>
> Thanks,
> Konstantina
>
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