I assume that the "AAA" below (without commas between) is a typo? Using the environment variable X10_HOSTLIST=A,A,A,A,B,B,B,B,B,B,B,B,B,B,B,B should work, as would any other combination of 4 A's and 12 B's. Setting it to X10_HOSTLIST=A,B,B,B would also do the job, since it will repeat. You can also use X10_HOSTFILE, and point it to a file with 16 lines, four of which are A, and the remaining are B (or one A, and three B's).
- Ben
From: "Zhijun Hao" <haozhijun.fu...@gmail.com>
To: x10-users <x10-users@lists.sourceforge.net>,
Date: 12/29/2013 03:46 AM
Subject: [X10-users] How can I distribute different number of places on
each host?
Hello,
Did anyone know how to distribute different number of places in X10 on
each host ?
For example, if there are two machines, A and B,
in A, there are 4 cores, while in B, there are 12 cores.
So I want to deploy 4 places on A and 12 places on B.
When I use "X10_NPLACES=16 X10_HOSTLIST=A,B ./a.out" to invoke the
application, the places are evenly divided.
Since the document said the hosts are wrapped, I try to use "X10_PLACES=16
X10_HOSTLIST=A,AAA,B,B,B,B,B,B,B,B,B,B,B,B",
but it seems that it doesn't work.
How can I solve this problem? Thanks.
Best Regards,
Zhijun Hao
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