Hello,
Thanks for your answer,
I didn't find the implementation,
Can you give me exactly the lines of code that permit me to do that, how can
I transform my xml document (string) to a xmlDocument and return It in my
external,
Thank you very much,
2008/11/17 David Bertoni <[EMAIL PROTECTED]>
> Anas EL HAJJAJI wrote:
>
>> Hi,
>>
>> My problem is :
>>
>> In a XSL file I make a call to an external function :
>>
>> *<xsl:value-of select="external:ListToXML()"/>*
>>
>> The function ListToXML() is like thatt :
>>
>> *XObjectPtr NGATranslatorXSLFunctionListToXML::execute(
>> XPathExecutionContext& io__executionContext,
>> XalanNode* io__context,
>> const XObjectArgVectorType& i__args,
>> const LocatorType* i__locator) const
>> {
>> string l__xml;
>> l__xml = "<exemple>exemple1</exemple><exemple>exemple2</exemple>";
>> return io__executionContext.getXObjectFactory().createString(
>> XalanDOMString(
>> l__xml.c_str())
>> );
>> }
>> *
>>
>> What I get in output (after transformation) is a XML part like that :
>>
>> *& l t ; exemple & g t ;exemple1** **& l t ; **/exemple**& g t ; **& l t
>> ;**exemple**& g t ;**exemple2**& l t ;**/exemple**& g t ;*
>>
>> It's encode the < to *& l t ;*
>> and *> *to* **& g t ;*
>>
> Yes, because you're returning a string.
>
>
>> How can I get a correct XML part ?
>>
> Take a look at the document() function and how it works. The
> implementation is in src/xalanc/XSLT/FunctionDocument.hpp. You essentially
> want to parse the markup into a document, and return the node in a node-set.
>
> Dave
>
--
Anas EL HAJJAJI
Ingénieur Étude et Développement
Sagem Sécurité Maroc
GSM : +212 66 06 94 14
[ENSIAS'08]
