dleslie 01/01/25 10:37:25
Modified: java/xdocs/sources/xalan faq.xml
Log:
Added faq from Dave Marston on retrieving nodes from default namespaces.
Revision Changes Path
1.3 +16 -2 xml-xalan/java/xdocs/sources/xalan/faq.xml
Index: faq.xml
===================================================================
RCS file: /home/cvs/xml-xalan/java/xdocs/sources/xalan/faq.xml,v
retrieving revision 1.2
retrieving revision 1.3
diff -u -r1.2 -r1.3
--- faq.xml 2001/01/24 15:36:38 1.2
+++ faq.xml 2001/01/25 18:37:19 1.3
@@ -94,7 +94,6 @@
<p>For more information, see <link idref="getstarted"
anchor="classpath">Setting up the system classpath</link>.</p></a>
</faq>
-
<faq title="Stylesheet validation">
<q>How do I validate an XSL stylesheet?</q>
<a>
@@ -105,5 +104,20 @@
XML.</p>
<p>You can use the xsl:stylesheet doctype defined in xsl-html40s.dtd
for stylesheets that generate HTML.</p>
</a>
- </faq>
+ </faq>
+
+ <faq title="Retrieving nodes in the default namespace">
+ <q>XPath isn't retrieving nodes that are in the default namespace I
defined. How do I get them?</q>
+ <a><p>If you are looking for nodes in a namespace, the XPath expression
must include a namespace prefix that you have mapped to the
+ namespace with an xmlns declaration. If you have declared a default
namespace, it does not have a prefix (see
+ <jump href="http://www.w3.org/TR/xpath.html#node-tests";>XPath Node
Tests</jump>). In order to construct XPath expressions
+ to retrieve nodes from this namespace, you must add a namespace
declaration that provides a prefix you can include in the XPath
+ expressions.</p>
+ <p>Suppose, for example, you you want to locate nodes in a default
namespace declared as follows:<br/>
+ <code>xmlns="http://my-namespace";</code></p>
+ <p>Add a nampespace declaration with a prefix:<br/>
+ <code>xmlns:foo="http://my-namespace";</code></p>
+ <p>Then you can use foo: in your XPath expression.</p>
+ <p>Hint: Don't use default namespaces, and the problem doesn't
arise.</p></a>
+ </faq>
</faqs>
