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http://nagoya.apache.org/bugzilla/show_bug.cgi?id=2862

*** shadow/2862 Fri Jul 27 12:43:54 2001
--- shadow/2862.tmp.22085       Sat Jul 28 08:49:44 2001
***************
*** 5,11 ****
  |       Status: NEW                         Version: CurrentCVS              |
  |   Resolution:                            Platform: All                     |
  |     Severity: Blocker                  OS/Version: All                     |
! |     Priority: Other                     Component: org.apache.xalan.xsltc  |
  +----------------------------------------------------------------------------+
  |  Assigned To: [EMAIL PROTECTED]                                     |
  |  Reported By: [EMAIL PROTECTED]                                          |
--- 5,11 ----
  |       Status: NEW                         Version: CurrentCVS              |
  |   Resolution:                            Platform: All                     |
  |     Severity: Blocker                  OS/Version: All                     |
! |     Priority: High                      Component: org.apache.xalan.xsltc  |
  +----------------------------------------------------------------------------+
  |  Assigned To: [EMAIL PROTECTED]                                     |
  |  Reported By: [EMAIL PROTECTED]                                          |
***************
*** 164,167 ****
  </contact>
  <followup><contact>Lin Molloy</contact></followup>
  </entry>
! </calendar>
--- 164,176 ----
  </contact>
  <followup><contact>Lin Molloy</contact></followup>
  </entry>
! </calendar>
! 
! ------- Additional Comments From [EMAIL PROTECTED]  2001-07-28 08:49 -------
! Tried to find a work-around but can't. The problem is not tied to using
! for-each. Even with 
!   <xsl:apply-templates select="document(string($otherfile))/calendar/*" />
! 
! a template matching on * is invoked and within it a copy-of select="." 
! copies the whole node, but there doesn't seem to be anyway to get the attributes
! of the node, which are used to decide whether to do the copy-of, or not.

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