xsl:variable problem

[Luis Villar]

I want create a jsp page applying the following xsl   <?xml version="1.0" encoding='ISO-8859-1'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:import href="Homepage.xsl" /> <xsl:variable name="selectedTemplateForBlocknoticia_1"> text <compositor:formatBlock blockXSLPath="noticiaDestacada.xsl"> <compositor:getOutput block="noticia" index="1" /> </compositor:formatBlock> </xsl:variable>   <xsl:template match="/"> <xsl:apply-templates select="page" /> </xsl:template> </xsl:stylesheet> where Homepage.xsl contains   <?xml version="1.0" encoding='ISO-8859-1'?> <xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" > <xsl:output method="html" indent="yes" /> <xsl:template match="page_block[@type='noticia' and @index_num='1']" > Procesando bloque <br/> <xsl:value-of select="$selectedTemplateForBlocknoticia_1" /> <br/> </xsl:template> </xsl:stylesheet>   to de xml   <?xml version="1.0" encoding='ISO-8859-1'?> <page> <page_block type="noticia" index_num="1"> <noticia id="1000"><atribute id="10"><value>1</value> </atribute><atribute id="1"><value>1</value></atribute> </noticia> </page_block> </page>   The problem is that where the value of the variable selectedTemplateForBlocknoticia_1 must appear only "text" appears, "<compositor:formatBlock blockXSLPath="noticiaDestacada.xsl"> <compositor:getOutput block="noticia" index="1" /> </compositor:formatBlock>" is ignored and it�s not included in the output file .... where is my error? ... can anybody help me?   thanks