How to test if transformed xml code is compliant with a DTD ?

[Stefan Geelen]

Hi,   I have following problem:   I have xml file with some data:   <?xml version="1.0" encoding="UTF-16"?> <?xml-stylesheet type="text/xsl" href="example.xsl" ?> <data>   <block>      Hello World   </block> </data>   I have a xsl file that needs to transform the xml data to another xml format compliant with the test.dtd specification:   <?xml version="1.0" ?> <xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform" version="1.0"> <xsl:output method="xml" indent="yes"  doctype-system="test.dtd" encoding="UTF-16" />   <xsl:template match="/">   <content>     <type1> <xsl:value-of select="data/block"/> </type1>   </content> </xsl:template> </xsl:stylesheet>   Now I use following code to do the transformation (partially reproduced) ... if(tfactory.getFeature(SAXSource.FEATURE)) {   // Standard way of creating an XMLReader in JAXP 1.1.   SAXParserFactory pfactory= SAXParserFactory.newInstance();     // Turn on support for XML namespaces.   pfactory.setNamespaceAware(true);     // Turn on validation.   pfactory.setValidating(true);     // Get an XMLReader.   reader = pfactory.newSAXParser().getXMLReader();     // Instantiate an error handler any errors or warnings that occur   // as the XMLReader is parsing the XML input.   reader.setErrorHandler(handler); ...   Now appareantly the validation is done on the INCOMING xml sheet, not on the TRANSFORMED xml sheet .   I need to know if the generated xml code is compliant with the test.dtd mentioned in the xsl sheet.   I looked in the API but could not find a solution for this problem.   How can I achieve this ?   Regards,   Stefan