<xsl:template match="oc-value['{.}'='mValue2']">
</xsl:template>
The predicate '{.}'='mValue2'is always false, since you're comparing two
string literals which are not equal. It looks like you're confusing
attribute value templates with match patterns. Try this instead:
<xsl:template match="oc-value[. = 'mValue2']">
</xsl:template>
Dave
"Monica Ferrero"
<[EMAIL PROTECTED] To: [EMAIL PROTECTED]
arconi.com> cc:
Subject: Problems to compare
the value of a node
02/15/2002 09:11
AM
Hi!
I'm using Xalan 2.3.0 to do tranformations in dsml files. I'd like to be
able to have a template that selects a given node knowing its content. The
concrete example is removing one of the <oc-value> nodes knowing its
content, ie 'mValue2' (that is really the only way of distinguish one
<oc-value> node from the rest, given that the position can be arbitrary).
I was trying something like the following, that doesn't match the node:
<?xml version="1.0"?>
<xsl:stylesheet xmlns:xsl="http://www.w3.org/1999/XSL/Transform"; version
="1.0">
<xsl:template match="oc-value['{.}'='mValue2']">
</xsl:template>
</xsl:stylesheet>
An example dsml input file would be:
<?xml version="1.0"?>
<dsml>
<directory-entries>
<entry dn="cn=B, cn=C">
<objectclass>
<oc-value>mValue1</oc-value>
<oc-value>mValue2</oc-value>
<oc-value>mValue3</oc-value>
</objectclass>
<attr name="cn">
<value>B</value>
</entry>
</directory-entries>
</dsml>
Thank you very much for your help,
Monica Ferrero
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