Ilene,
Strange! That's the result I was hoping to get. How come you
get the result I need and I don't get it. :-(
But thanks for your reply as well as your test result. I'll try again.
Regards,
Pae
> Hi ,
>
> I tried the sample code that you provided and it seems to be working. I
> added a couple of snippets to print out the nodes that were being
returned:
>
> After the query:
> node = XPathAPI.selectSingleNode(xmlDoc, "//[EMAIL
> PROTECTED]'10099']/*");
>
> I tried:
> System.out.println("Node: " + node.getNodeName());
>
> and was returned:
> Node: DemoInfo
>
> After the second query:
> NodeIterator nl = XPathAPI.selectNodeIterator(node, "./*");
>
> I tried:
> Node n = null;
> while ((n = nl.nextNode()) != null) {
> System.out.println("Got node: " + n.getNodeName());
> }
>
> and was returned:
>
> Got node: Age
> Got node: Gender
>
> Is this different from the results you were seeing or expecting?
>
> Ilene.
>
>
>
>
>
> "Pae Choi"
> <[EMAIL PROTECTED] To:
<[EMAIL PROTECTED]>, Joseph Kesselman/Watson/[EMAIL PROTECTED]
> k.net> cc:
> Subject: Re: 1st
parameter, "Node context Node" in the XPathAPI's methods
> 11/25/2002 01:00
> PM
>
>
>
>
>
> I was hoping that, but did not work in that way. I have posted
> source code, including the XML doc. If you see the Java code and
> better to test it to see the result.
>
>
> Pae
>
>
> > From the Javadoc:
> > contextNode - The node to start searching from.
> >
> > In other words, the note where evaluation of the XPath should start.
> >
> > ______________________________________
> > Joe Kesselman / IBM Research
>
>
>
>
