Hi,
As stated this is a faq, but just a little guidance might help... You should
look into the ancestor-or-self xpath axis, the local-name() and concat()
functions.
So, on any particular node you could use:
<xsl:for-each select="ancestor-or-self::*">
<xsl:value-of select="concat('/',local-name())"/>
</xsl:for-each>
which would give you '/foo/bar/baz'
from say:
<foo>
<bar>
<baz>
....
when matching the <baz> element
cheers
andrew
>
> >Is there a way to get the (X)Path of a node in an XML?
>
> This is a FAQ about XSLT in general. Have you checked
> http://www.dpawson.co.uk
> for information?
>
> >It will be useful in many cases for my project.
>
> You should clarify (to yourself, at least) what the uses are.
> There may be more efficient ways to do what you want.
> .................David Marston
>
>
>
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