Hi Karsten,
A node-set is truly a set of nodes, so the union of two node-sets
will contain only unique nodes. You could write either of the following,
depending on how early you want to get the single node set.
<xsl:variable name="nodes1and2"
select="key('element_index', $id1)|
key('element_index', $id2)"/>
or
<xsl:variable name="nodes1and2" select="$node1|$node2"/>
If you happen to have another variable (say, idns) whose value is a
node-set that contains nodes whose values when converted to strings are
equal to $id1 and $id2, you could also write the following.
<xsl:variable name="nodes1and2"
select="key('element_index', $idns)"/>
Thanks,
Henry
------------------------------------------------------------------
Henry Zongaro Xalan development
IBM SWS Toronto Lab Tie Line 969-6044; Phone (905) 413-6044
mailto:[EMAIL PROTECTED]
"Karsten Theis" <[EMAIL PROTECTED]>
02/28/2003 04:24 AM
Please respond to karsten.theis
To: "XALAN Mailing List (E-Mail)" <[EMAIL PROTECTED]>
cc:
Subject: Unique merging of node-sets
Hi,
I'm looking for a way to merge to node-sets into one, but I don't want to
have duplicate elements.
The following XPATH works, but it's slow and should be replaced by two
xsl:key statements:
Working XPATH (It is possible, that $id1 = $id2):
<xsl:variable name="all_nodes" select = "//[EMAIL PROTECTED] or @id=$id2]"/>
xsl:key statement:
<xsl:key name="element_index" match="*" use="@id"/>
<xsl:variable name="node1" select = "key('element_index', $id1)"/>
<xsl:variable name="node2" select = "key('element_index', $id2)"/>
How can I merge "node1" and "node2" into a node-set?
And what happens, if $id1 = $id2 ?
Ciao, Karsten
