Thanks Dimitry! I'm off to the races! BTW, I hope to work out a complete xalan example of doing this. I'll send a copy to you.
Roger ----- Original Message ----- From: "Voytenko, Dimitry" <[EMAIL PROTECTED]> To: "Roger I Martin PhD" <[EMAIL PROTECTED]>; <[EMAIL PROTECTED]> Sent: Monday, August 04, 2003 5:18 PM Subject: RE: xml with DOCTYPE defined and getting the root element Hi, if you expect your <xsl:apply-templates /> in line 49 to match template: <xsl:template match="math" name="math"> in line 9, it's not gonna do that. Your root element is defined in the math namespace. You need to change it to (note "math:") <xsl:template match="math:math" name="math"> For further references I'd advise to change your stylesheet to: <xsl:output method="xml"/> <xsl:template match="/"> <xsl:copy-of select="."/> </xsl:template> just to see what your source document looks like after it's been processed by xml parser. thanks, Dimitry -----Original Message----- From: Roger I Martin PhD [mailto:[EMAIL PROTECTED] Sent: Monday, August 04, 2003 13:48 To: [EMAIL PROTECTED] Subject: Re: xml with DOCTYPE defined and getting the root element Yes but when I go for the element child either with match="/*" or apply-templates, no further template matching occurs. apply-templates of any kind don't work. There must be something else I am doing wrong. ----- Original Message ----- From: "Joseph Kesselman" <[EMAIL PROTECTED]> To: <[EMAIL PROTECTED]> Sent: Monday, August 04, 2003 4:31 PM Subject: Re: xml with DOCTYPE defined and getting the root element > > > > > In XPath/XSLT terms, the "document root" is the same thing the DOM calls > the Document Node, or SAX calls the Document event. If you want the > top-level element, you need to retrieve the element child of the root node. > > ______________________________________ > Joe Kesselman, IBM Next-Generation Web Technologies: XML, XSL and more. > "The world changed profoundly and unpredictably the day Tim Berners Lee > got bitten by a radioactive spider." -- Rafe Culpin, in r.m.filk > >
