Hi
I want to sort a nodeset using xsl:sort and am finding that the nodeset will be
sorted if there is an enclosing element but not if there isn't.
In an attempt to clarify, please look at the following example. Incidentally,
it doesn't make any difference if I build the nodeset on the fly as I have done
here or take it from an input file.
I can't understand why sort 1 doesn't work but sort 2 does. Can anybody
clarify? Thanks, Graeme
<xsl:template name="sort-test">
<!-- some elements that I want to output in order -->
<xsl:variable name="elements-to-sort">
<element>quick</element>
<element>brown</element>
<element>fox</element>
<element>lazy</element>
<element>dog</element>
</xsl:variable>
<!-- wrap those elements in an enclosing "words" element -->
<xsl:variable name="enclosed-elements-to-sort">
<words>
<xsl:copy-of select="$elements-to-sort" />
</words>
</xsl:variable>
<!-- sort 1- this does not sort the elements but outputs them in their
original order -->
<xsl:apply-templates select="xalan:nodeset($elements-to-sort)">
<xsl:sort select="." />
</xsl:apply-templates>
<xsl:apply-templates select="xalan:nodeset($enclosed-elements-to-sort)"
mode="sort" />
</xsl:template>
<!-- sort 2- this template successfully sorts the elements -->
<xsl:template match="words" mode="sort">
<!-- what is the difference between the effect of the call
to apply-templates here and the one that doesn't work? -->
<xsl:apply-templates>
<xsl:sort select="." />
</xsl:apply-templates>
</xsl:template>
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