On Mon, 9 Feb 2004 [EMAIL PROTECTED] wrote: > Lainaus Joona Palaste <[EMAIL PROTECTED]>: > > < On Mon, 9 Feb 2004, Kielen, Agnes wrote: > < > < > Try: > < > > < > <xsl:stylesheet version="1.0" > < xmlns:xsl="http://www.w3.org/1999/XSL/Transform";> > < > <xsl:template match="/document"> > < > <document> > < > <xsl:for-each select="node[(position() mod 2) = 1]"> > < > <group> > < > <xsl:copy-of select=". | following-sibling::node[1]"/> > < > </group> > < > </xsl:for-each> > < > </document> > < > </xsl:template> > < > > < > </xsl:stylesheet> > < > < Thanks for the advice. What if I want the number of <node> nodes to go > < to a single <group> node to depend on some attribute in the original XML > < document? Say, for example: > < > < <document> > < <nodes width="3"> > < <node>1</node> > < <node>2</node> > < <node>3</node> > < <node>4</node> > < <node>5</node> > < <node>6</node> > < <node>7</node> > < <node>8</node> > < </nodes> > < </document> > > Something like (not tested): > > <xsl:template match="/document/nodes"> > <xsl:variable name="module" select="@width"/> > <document> > <xsl:for-each select="node[(position() mod $module) = 1]"> > <group> > <xsl:copy-of select=". | > following-sibling::node[position()<$module]"/> > </group> > </xsl:for-each> > </document> > </xsl:template> > > > > < > < How can I make this transform to this? > < > < <document> > < <group> > < <node>1</node> > < <node>2</node> > < <node>3</node> > < </group> > < <group> > < <node>4</node> > < <node>5</node> > < <node>6</node> > < </group> > < <group> > < <node>7</node> > < <node>8</node> > < </group> > < </document> > < > < In other words, the "length" attribute defines how many <node> nodes go > < under a single <group> node. If there are not enough nodes, then all > < that are left are used. Is this possible in XSLT?
That's great, thanks Agnes and Jarkko! Joona Palaste [EMAIL PROTECTED]
