Thank you, Morris -----Urspr�ngliche Nachricht----- Von: Morris Kwan [mailto:[EMAIL PROTECTED] Gesendet: Dienstag, 24. Februar 2004 17:21 An: Lenharcik, Juraj Cc: [EMAIL PROTECTED] Betreff: Re: XSLTC with SQL extension
Hi, Juraj SQL extension is not supported in XSLTC at the moment. You can refer to the page (http://xml.apache.org/xalan-j/extensions_xsltc.html) for more information on what extensions are supported in XSLTC. Regards, Morris Kwan XSLT Development IBM Toronto Lab Tel: (905)413-3729 Email: [EMAIL PROTECTED] [EMAIL PROTECTED] -systems.com To 02/24/2004 11:04 [EMAIL PROTECTED] AM cc Subject XSLTC with SQL extension Hello, I have got an problem with the compile of my sheets which including the SQL extension. I get this exception: [java] Fehler beim ?berpr�fen des Typs des Ausdrucks 'FilterParentPath(funcall(org.apache.xal an.lib.sql.XConnection:getError, []), step("child", 14))'. ==> Error while check of the statement ...... I tried to cast the type to string and node-set without any effects. <xsl:if test="not(boolean(sql:connect($db, $driver, $datasource, $username, $passwd)))"> <xsl:value-of select="log4j:traceError('Error connecting to the database: RASANT')"/> <xsl:variable name="errorMsg"> <xsl:value-of select="string(sql:getError($db)/ext-error)"/> </xsl:variable> <xsl:value-of select="log4j:traceError($errorMsg)"/> </xsl:if> Does someone see an error. Or does anyone knows how to cast these types? Thanks Juraj
