Hello.
"Puneet Kathuria" <[EMAIL PROTECTED]> wrote on 2005-04-26 01:37:00 PM:
> Trying to execute the sample provided at following location:
>
> Samples\servlet\SimpleXSLTServlet
>
> In the birds.xsl, I included another XSL say "search.xsl", the xalan
> searches for that XSL in following directory:
>
> C:\Program Files\Apache Software Foundation\Tomcat 5.0\bin\search.xsl
>
> basically the directory from where tomcat wa started. It should look
> for the xsl in context which was determined in the servlet by
>
> Source xmlSource = new StreamSource(new URL("file", "", ctx+"birds.
> xml").openStream());
Thanks for pointing this out. This is a problem in the sample
itself. The problem is in the way the servlet sample creates the
StreamSource - it should specify the system ID on the StreamSource object
(either on the constructor or through the setSystemId method) so that
Xalan can correctly resolve relative URI references.
Alternatively, the sample could use a URIResolver.
Thanks,
Henry
------------------------------------------------------------------
Henry Zongaro Xalan development
IBM SWS Toronto Lab T/L 969-6044; Phone +1 905 413-6044
mailto:[EMAIL PROTECTED]
