Henry Zongaro wrote:
Hi, Stephane.
"Stephane Dion" <[EMAIL PROTECTED]> wrote on 2005-10-20 02:51:26 PM:
Like you mention, I would like to have the same input XML as my
output XML (with the netPrice sorted) but the attributes are not
copied even if I have the xsl:copy. Can you help me on this?
The default value for the select attribute of the xsl:apply-templates
instruction is "*", which means that templates matching the element
children of the current node will be applied.
Not quite true. If the xsl:apply-templates instruction does not have a
select attribute, then default behavior is to select all of the children
of the current node.
http://www.w3.org/TR/xslt#section-Applying-Template-Rules
"In the absence of a select attribute, the xsl:apply-templates
instruction processes all of the children of the current node, including
text nodes."
So the real default is "node()".
See [1] for tutorial information about XSLT. You can find information
about the Mulberry XSL Mailing List at [2], which is a good place to ask
questions about XSLT. The xalan-j-users mailing list is really intended
as a place to discuss issues that are specific to the Xalan-J processors.
I agree with Henry. You will not find a better resource for XSLT
questions than the Mulberry list.
Dave
