> As we have xs:any in xerces for any namespace usage , how do I > achieve in xslt ? I could not find any construct in xsl as we have > in schema language.
XSLT 1.0 and XPath 1.0 are not schema-aware. (That was added in the 2.0 version of these, which Xalan does not yet support.) If you want to match names without looking at the namespace, you can use wildcard QNames such as *:foo, or match on a wildcard and then qualify that with a predicate.
