> On Mar 9, 2015, at 7:10 PM, John Tsombakos <[email protected]> wrote:
> 
> Well, I just tried with the newly released Xcode 6.2, and still the editor 
> does not recognize the passed in variables to the block. I’m trying to find 
> another call that has a completion handler to see if it’s just this call or 
> is a bigger problem.

Hi John,

FYI, there are no significant Swift changes in Xcode 6.2, they are all rolling 
into the 6.3 betas.  The only swift-related change in 6.2 is related to 
nullability audits of WatchKit (which didn’t exist in 6.1.1).

-Chris


> 
> 
>> On Mar 5, 2015, at 7:09 PM, John Tsombakos <[email protected] 
>> <mailto:[email protected]>> wrote:
>> 
>>> 
>>> On Thu, Mar 5, 2015 at 1:54 PM, Fritz Anderson <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> On 5 Mar 2015, at 6:24 AM, John Tsombakos <[email protected] 
>>> <mailto:[email protected]>> wrote:
>>> 
>>>> I entered this line of code:
>>>> 
>>>>         let task = session.dataTaskWithRequest(request, completionHandler: 
>>>> { (myData, myResponse, myError) -> Void in
>>>> 
>>>> 
>>>> 
>>>>         });
>>>> 
>>>> and when I go to write code in the completion handler block, Xcode does 
>>>> not recognize the variables that are being passed in - in this case 
>>>> myData, myResponse and myError.
>>>> 
>>>> Ami I doing something wrong, or does XCode just not know how to do this?
>>> 
>>> Quincey’s advice is sound as to the coding style. Let me embarrass myself 
>>> once again; I’m working my way up to total humiliation, which gets you BOGO 
>>> on all Developer Programs renewals and the exemption of your choice from 
>>> the app-review guidelines:
>>> 
>>> My experience is that when the compiler claims not to recognize a function 
>>> parameter, it’s because something up the chain isn’t unwrapped (such as 
>>> session, here).
>>> 
>> 
> 
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