From: Grygorii Strashko <grygorii_stras...@epam.com>
The current code in generate_uboot_images() does not detect arm64 properly
and always generates ARM u-boot image, because below command
file -L $XEN
returns string which may contain "Aarch64" or "ARM64", and, in the later
case, the current code will mistakenly identify Xen binary as "ARM".
This causes Xen boot issues.
Fix it by searching for "ARM64|Aarch64" for AArch64 binary detection.
- mkimage -l xen.ub
Before:
Image Type: ARM Linux Kernel Image (uncompressed)
After:
Image Type: AArch64 Linux Kernel Image (uncompressed)
Signed-off-by: Grygorii Strashko <grygorii_stras...@epam.com>
---
changes in v2:
- check for "Aarch64" in addition to "ARM64"
scripts/uboot-script-gen | 6 +++---
1 file changed, 3 insertions(+), 3 deletions(-)
diff --git a/scripts/uboot-script-gen b/scripts/uboot-script-gen
index 527b70dfdc4b..f3ca787e557f 100755
--- a/scripts/uboot-script-gen
+++ b/scripts/uboot-script-gen
@@ -824,13 +824,13 @@ function linux_config()
generate_uboot_images()
{
- local arch=$(file -L $XEN | grep "ARM")
+ local arch=$(file -L $XEN | grep -E 'ARM64|Aarch64')
if test "$arch"
then
- arch=arm
- else
arch=arm64
+ else
+ arch=arm
fi
mkimage -A $arch -T kernel -C none -a $memaddr -e $memaddr -d $XEN
"$XEN".ub
--
2.34.1
