but what about the memory leak for Xml_DOM_Node_Impl *p ;
who will release that :
Xml_DOM_Node* Xml_DOM_Node::getFirstChild() const
{
DOM_Node node =
pdomnodeimpl->domnode.getFirstChild();
Xml_DOM_Node_Impl* p = new Xml_DOM_Node_Impl;
p->domnode = node;
Xml_DOM_Node* pXmlDOMNode = new Xml_DOM_Node(p);
return pXmlDOMNode;
// WHO WILL release memory pointed by p
}
main () {
Xml_DOM_Node* xmlnode2 = xmlnode1.getFirstChild();
// do some work
.
.
.
delete xmlnode2;// caller deletes the memory
}
who is going to delete that ?? may be i am stupid but jst a dumb question.
-----Original Message-----
From: Adams, David [mailto:[EMAIL PROTECTED]]
Sent: Tuesday, June 12, 2001 3:27 PM
To: '[EMAIL PROTECTED]'
Subject: RE: wrapping Xerces API in my code !!
If you create an assignment operator in your class, things would be
easier. But, to answer your question, the caller is responsible for freeing
the allocated memory returned by a called function:
Xml_DOM_Node* Xml_DOM_Node::getFirstChild() const
{
// get the node
DOM_Node node =
pdomnodeimpl->domnode.getFirstChild();
// create your struct and wrap the node in it
Xml_DOM_Node_Impl* p = new Xml_DOM_Node_Impl;
p->domnode = node;
// create your returnable class with the wrapped
struct in it.
// The caller is responsible for deleting the memory
Xml_DOM_Node* pXmlDOMNode = new Xml_DOM_Node(p);
return pXmlDOMNode;
}
void main(void)
{
.
.
.
DOM_Node n; // again, some valid node
Xml_DOM_Node_Impl* impl = new Xml_DOM_Node_Impl;
Xml_DOM_Node xmlnode1(impl);
Xml_DOM_Node* xmlnode2 = xmlnode1.getFirstChild();
// do some work
.
.
.
delete xmlnode2;// caller deletes the memory
}
> -----Original Message-----
> From: Awasthi, Anand [SMTP:[EMAIL PROTECTED]]
> Sent: Tuesday, June 12, 2001 3:11 PM
> To: '[EMAIL PROTECTED]'
> Subject: RE: wrapping Xerces API in my code !!
>
> but what about the memory leak ( due to pointer creation with in function
> body ) ??
>
>
>
>
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