Re: How to get the repetition property ?

[Khaled Noaman]

Hi Peter,
The repetition information is saved in the content spec node
information of a SchemaElementDecl. So, you are right about checking
the content spec node of elements. An element can have a sequence as it
content spec node (e.g. min=2 max=unbounded), in case you want to check
for that.
So, your code should work.
I noticed the following in your code snippet:
    >> if (!cSpecNode)
You need to remove the negation from the condition.
Regards,
Khaled
"Peter A. Volchek" wrote:
Line from *.xsd
<xsd:element name="A" type="TypeA" minOccurs="1" maxOccurs="unbounded"
nillable="true"/>
How could I get the information about minOccurs="1" maxOccurs="unbounded"
properties ?
I expected that following code will return mw what I want
    SchemaGrammar* grammar = (SchemaGrammar*)
parser.getValidator().getGrammar();
    RefHash3KeysIdPoolEnumerator<SchemaElementDecl>
elemEnum =
grammar->getElemEnumerator();
    if (elemEnum.hasMoreElements())
    {
        while(elemEnum.hasMoreElements())
        {
           
// Element's properties
           
const SchemaElementDecl& curElem = elemEnum.nextElement();
           
ContentSpecNode* cSpecNode = curElem.getContentSpec();
            if(
!cSpecNode) {
    switch( cSpecNode->getType() )
    {
        case ContentSpecNode::Leaf:            
cout << "Leaf"; break;
        case ContentSpecNode::ZeroOrOne:       
cout << "ZeroOrOne"; break;
        case ContentSpecNode::ZeroOrMore:      
cout << "ZeroOrMore"; break;
// That is what I need
    ...
    }
But this does not work
Could you suggest smth ?
Peter A. Volchek
Software Engineer
Metis International, Inc.
[EMAIL PROTECTED]
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