At 01.12 12/05/2004 +0100, vithal sripada wrote:
hi the machine on which i'm working is as follows......
Machine hardware: sun4u OS version: 5.9 Processor type: sparc Hardware: SUNW,Sun-Blade-1000
and when i've typed
> gcc $version gcc: tcsh: No such file or directory gcc: 6.12.00: No such file or directory gcc: (Astron): No such file or directory gcc: 2002-07-23: No such file or directory gcc: (sparc-sun-solaris): No such file or directory gcc: options: No such file or directory gcc: 8b,nls,dl,al,rh,color,filec: No such file or directory gcc: no input files
You should type "gcc --version" to get the version of your compiler
i've downloaded the binary version and extracted versoin is currently in my home directory and name of the folder is "xerces"
echo $HOME /home/vsripada
so my .cshrc looks like this
set path = ($path $HOME/xerces/bin)
setenv XERCESCROOT '$HOME'/xerces/include
as far as i understood XERCESCROOT should point out to directory where all the include files are present so is this correct. ??? as the simple SAXPrint.cpp program includes some files from
xercesc/util folder
No, XERCESCROOT should point to $HOME/xerces, with no quotes, like in
setenv XERCESCROOT $HOME/xerces
setenv XERCESCOUT '$HOME'/xerces
this XERCESCOUT has been defined after seeing the Makefile.in that comes along with sample prgm.....as in that file this variable has been used to for specfying where object and exectuables should be placed......as compiling it....
You can avoid defining this variable
setenv LD_LIBRARY_PATH $XERCESCOUT/lib this points to lib directory
Change it to be
setenv LD_LIBRARY_PATH $LD_LIBRARY_PATH:$XERCESCROOT/lib
setenv CLASSPATH '$LD_LIBRARY_PATH':'$LD_LIBRARY_PATH':'$CLASSPATH'
setenv CLASSPATH '$XERCESCOUT'/lib/libxerces-c.so:'$XERCESCOUT'/lib/libxerces-c.so.25:'$XERCESCOUT'/lib/libxerces-c.so.25.0:'$LD_LIBRARY_P$
As I told you, CLASSPATH is only used by Java program, why do you want to define it?
explicitly specfying the class path for the 3 files in the lib directory.....
when i go to bin directory and give a xml file ....it prints me the file.....
but when i want to compile the sample prgm file present in SAXPrint directory...i'm getting problem.....i've a very basic doubt...how do i make use of makefile.in present in the SAXPrint ........
should i simply type ...Makefile.in or
do i need to make some changes to it (the makefile.in) ......?
You need to build a Makefile from Makefile.in, using:
./runConfigure -p solaris gmake
Alberto
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