It works fine, you saved me!! Thanks a lot!!!!! Enrico.
At 15:33 04/12/2001 +0530, you wrote:
InputStream inStream = new ByteArrayInputStream(nextBuf); org.xml.sax.InputSource inSource = new org.xml.sax.InputSource(inStream); //Creates the input source for parser. SaxParser sp = new SaxParser(); sp.parse(inSource);
The above code might work.
regards, Sridhar.
-----Original Message----- From: Enrico Paolo Lelli [mailto:[EMAIL PROTECTED] Sent: Tuesday, December 04, 2001 3:24 PM To: [EMAIL PROTECTED] Subject: Need help
Hi all, I'm looking for advices about Xerces Parser. In my code I have a client sending xml string: the server write down this string in a file and then give it to Xerces parser to process it. I would like to know if I might directly parse the string, without writing the file. Here is my actual code:
dis.receive(); command = dis.readUTF(); byte [] nextBuf = command.getBytes(); String fileName = "message.xml"; FileOutputStream fos = new FileOutputStream(fileName ); fos.write(nextBuf); SaxParser sp = new SaxParser(this); sp.performDemo(fileName );
I would like something like this:
dis.receive(); command = dis.readUTF(); SaxParser sp = new SaxParser(this); sp.performDemo(command );
Please help!!! :))
Tnx, Enrico.
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