Hi all,
I am not able to get different namespaces for a parent element and a child element even though I have defined different namespaces for both.
My xml request looks like :
<?xml version="1.0"
encoding="UTF-8"?>
<Envelope xmlns="http://schemas.xmlsoap.org/soap/envelope/">
<Body>
<EL1 generic="2.0" xmlns="urn:uddi-org:api_v2">
<EL2 xmlns="urn:uddi-org:repl">abcd</EL2>
</EL1>
</Body>
</Envelope>
This is parsed by SAXParser(xerces 1.4.3)
In my code of startElement method where namespace is passed as a parameter, for both EL1 and EL2, the namespace obtained is the same as EL1(i.e., the root element), even though for EL2, different namespace is used. How do I get the EL2 namespace?
From: JC [mailto:[EMAIL PROTECTED]
Sent: Thursday, June 20, 2002 10:28 PM
To: [EMAIL PROTECTED]
Subject: Re: How to identify the namespace?
This was what I needed! (The first part, not the second.) Thank you very much.
At 05:54 PM 6/20/2002 +0200, you wrote:
Hi,
If you use SAX2, you'll see a startPrefixMapping( prefix, nsuri ) event
before the startElement() event. Anyway, the startElement() event also passes
the namespace URI to you.
If you use DOM, you can get the namespace URI out of every element node.
Jan Dvorak
> Here is something that is bugging me... during the parsing of an RSS file,
> I need to be able to tell if it is a 0.9 RSS or a 1.0 RSS. Unlike RSS 0.91
> and 0.92, there is no "version" attribute. Here is what I have to work
> with:
>
> <rdf:RDF xmlns="http://my.netscape.com/rdf/simple/0.9/"
> xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#">
>
> This is an RSS 0.9 file.
>
> <rdf:RDF xmlns="http://purl.org/rss/1.0/"
> xmlns:rdf="http://www.w3.org/1999/02/22-rdf-syntax-ns#">
>
> This is an RSS 1.0 file.
>
> The only difference between the two is the xmlns value. However, I cannot
> figure out how to get ahold of it. During element parsing, I only have
> access to the xmlns:rdf value (as uri), the element name and the qname. The
> attributes length is zero.
>
> So how can I get ahold of the xmlns value during parsing?
>
> Thanks for any help!
>
>
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