Hi Ragu,
In addition to what rahul mentioned i think you need to set the following feature to false .
parser.setFeature("http://apache.org/xml/features/dom/defer-node-expansion"; ,false);
Regards venu
Rahul Srivastava wrote:
> Ragunath Marudhachalam wrote... > > Hi Rahul, > > Thanks for the tip. I'm using DOM Parser. I went thru the link u gave me, > but i didnt get to know how to use it. I mean to set the > property, and how to get the element name.
If you have read the docs, you will notice that the property current-element-node is readonly. You cannot set this property. To use this property, register an ErrorHandler with the DOM parser. Within the callback of the registered ErrorHandler, you need to do something like this: Element node = (Element)parser.getProperty("http://apache.org/xml/properties/dom/current-el ement-node"); if (node != null) { // now you have the node from where you can // traverse all the way back to the root System.out.println(node.getNodeName()); System.out.println(node.getParentNode().getNodeName()); }
Hope that helps.
Cheers, Rahul.
> If you dont mind, could u plz help me > as how to use > it or give me a small sample of how to use it, coz so far i have > only used > setting features. I am very thankful for your time and help. > > Ragu > CircuitVision > > > > -----Original Message----- > From: Rahul Srivastava [mailto:[EMAIL PROTECTED] > Sent: Tuesday, May 13, 2003 2:14 AM > To: [EMAIL PROTECTED] > Subject: RE: How to get the full parent child path on schema validation. > > > Hi Ragu, > > You did not mention which parsing are you using viz. SAX/DOM parsing!. > > In case you are using DOM parsing, you can try using the property > dom/current-element-node, which will give you the current node. > You can then > traverse back from that node and get the full tree. > See: > http://xml.apache.org/xerces2-j/properties.html#dom.current-element-node > for more details. > > Cheers, > Rahul. > > > > > Ragunath Marudhachalam wrote... > > > > Hello All, > > > > I have been able to validate a xml document with a schema. I > do have the > > handler class and i'm able to print the error messages and > also the line > > number where the error has occured. For some reasons i need > to have the > > whole tree structure of the element where the error has occured. For > > example, if the xml document is like this, > > > > <a> > > <b> > > <c> > > <d> > > </d> > > > > </c> > > > > </b> > > > > </a> > > > > and the error is at the element <d>, then i need to get the whole tree > > structure from the root element, like a/b/c/d.... is it possible > > to get that > > in someway.. As far as i know, i havent found a direct method to do > > that...It would be a real help if anybody could suggest me > some method or > > with some sample code.... > > > > Thanks > > > > Ragu > > CircuitVision > > > > > > > > --------------------------------------------------------------------- > > To unsubscribe, e-mail: [EMAIL PROTECTED] > > For additional commands, e-mail: [EMAIL PROTECTED] > > > > > > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > > > --------------------------------------------------------------------- > To unsubscribe, e-mail: [EMAIL PROTECTED] > For additional commands, e-mail: [EMAIL PROTECTED] > >
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