Hi, I'm using Xfree86 V4.2.0 under Linux Red Hat V7.3. I want to use this X server in PseudoColor mode, and for this I set up in concordance the "/etc/X11/XF86Config-4" file. To start the X server from the "/etc/inittab" in "run level 5", instead of the call of "/etc/X11/prefdm", I call a file that makes "xinit /.xinitrc -- :0 -class PseudoColor -dpi 100X100".
The "/.xinitrc" file contains : # To grant access for any X host client xhost + # To turn off the screen saver xset s off # Loop to keep the X server alive... while [ true ] do sleep 10000 done In this context, when I look the default colormap that the server manages, with a specific X client "mcmap", there is 248 of 256 colors reserved and locked on the default colormap. If instead of the loop in the "/.xinitrc" file, I start the "mwm" windows manager, then there is no more free color in the default colormap, i.e. all the 256 colors are affected and locked. When I look the process that run under the system at this moment, I can't found any process that may take colors in the default colormap, like "xlogo" or others X11 applications. There is only "xfs" running at this point, in relation of the X server. So why there is 248 of 256 colors reserved and locked on the default colormap when the X server starts, and how can I start the XFree86 server, in order to have the minimum color taken by it in the default colormap? Is it possible to start the Xfree86 server with a specific "default colormap", i.e. with the first 16 colors affected as needed, and the others colors free? Thank's in advance for your answer, and have an happy new year, -- Regards, ------------------------- Patrice Martin ------------------------------ _______________________________________________ XFree86 mailing list [EMAIL PROTECTED] http://XFree86.Org/mailman/listinfo/xfree86
