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No, I am just using another xpath based on this use case.
----- Original Message -----
Sent: Thursday, September 25, 2003 3:14
PM
Subject: Re: Use cases
Shouldn't the query be like:?
"/movie/title[.='Gladiator']
----- Original Message -----
Sent: Thursday, September 25, 2003 9:10
AM
Subject: Use cases
Hi all,
I have tried using this XPath search on my XML collection
String xpath = "/movie/title='Gladiator'";
XPathQueryService service
=
(XPathQueryService)
collection.getService("XPathQueryService", "1.0");
ResourceSet resultSet
= service.query(xpath);
ResourceIterator results =
resultSet.getIterator();
while (results.hasMoreResources())
{
XMLResource resource =
(XMLResource) results.nextResource();
Node result =
resource.getContentAsDOM();
}
However, I get several nodes back as the result from the query and only
the last one gets in the Node structure, the rest is discarded.
Is there a way around to get all the results in the Node or in a DOM
document (maybe using a string)?
Regards,
Boris
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