Nima ,
Plz use the following API() xmlNodeListGetString(xmlDocPtr doc , xmlNodePtr list , int inline ) Get the (xmlDocPtr doc) from xmlParseFile(const char* filename) API or xmlParseMemory(const char* buffer , int size) Get the Current (xmlNodePtr list) for ur node <pic_file> by traversing the DOM Document Tree , until u encounter a node with xmlNodePtr->name as same as pic_file ( Take the help of xmlStrcmp() API ) . Say this node is xmlNodePtr pXmlNodePicFile Once u have this pXmlNodePicFile u cannot blindly use pXmlNodePicFile->content as the TEXT Content MyPicFileName.pdf is also a child node of the pXmlNodePicFile So pass the 1st child of pXmlNodePicFile to xmlNodeListGetString() API like this xmlNodeListGetString(doc, pXmlNodePicFile->children , 1) Regds, Lav ________________________________ From: [EMAIL PROTECTED] [mailto:[EMAIL PROTECTED] On Behalf Of Nima Tiran Sent: Tuesday, June 10, 2008 3:11 AM To: [email protected] Subject: [xml] Simple parsing XML question... Hi all, I'm newbie here and got a simple question: I'm parsing an XML file and having a node like: <pic_file>MyPicFileName.pdf</pic_file> in XML file, just wondering how can I retrieve "MyPicFileName" from this node? Thnx Nima DISCLAIMER: This email may contain confidential or privileged information for the intended recipient(s) and the views expressed in the same are not necessarily the views of Zensar Technologies Ltd. If you are not the intended recipient or have received this e-mail by error, its use is strictly prohibited, please delete the e-mail and notify the sender. Zensar Technologies Ltd. does not accept any liability for virus infected mails.
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