[XXE] AW: XXE - find out current year?

[Szabo, Patrick (LNG-VIE)]

Hello, 

Thanks a lot!
That really helped ^^

Regards


-----Urspr?ngliche Nachricht-----
Von: Hussein Shafie [mailto:hussein at xmlmind.com] 
Gesendet: Freitag, 29. Februar 2008 10:55
An: Szabo, Patrick (LNG-VIE)
Cc: xmleditor-support at xmlmind.com
Betreff: Re: XXE - find out current year?

Szabo, Patrick (LNG-VIE) wrote:
> I have an issue with the following line:
> 
>  
> 
> <cfg:set variable="curr_path" 
> expression="R:\Produktion\Print\ARD-Handbuch\*xxxx*\xml" 
> plainString="true"/>
> 
>  
> 
> The thing is:
> 
>  
> 
> I would like to automatically replace "*xxxx*" with the current year. Is 
> there a way to provide that?!
> 
>  
> 

<cfg:set variable="curr_path" 
expression="concat('R:\Produktion\Print\ARD-Handbuch\',XXXX,'\xml')" />

where XXXX is a XPath expression that returns current year. Note that 
you need to remove plainString="true".

Example:

<cfg:set variable="curr_path" 
expression="concat('R:\Produktion\Print\ARD-Handbuch\',(1900+date:getYear(date:new())),'\xml')"
 
xmlns:date="java:java.util.Date" />



I've tested the above solution using the following macro:
---
   <command name="currentYear" xmlns:date="java:java.util.Date">
     <macro >
       <sequence>
         <get 
expression="concat('R:\Produktion\Print\ARD-Handbuch\',(1900+date:getYear(date:new())),'\xml')"/>
         <command name="alert" parameter="%_" />
       </sequence>
     </macro>
   </command>

   <binding>
     <keyPressed code="F3" />
     <command name="currentYear" />
   </binding>
---