Hi, i get the following warning on every xmlRpcClient.execute() :
org.apache.commons.httpclient.SimpleHttpConnectionManager getConnectionWithTimeout WARNUNG: SimpleHttpConnectionManager being used incorrectly. Be sure that HttpMethod.releaseConnection() is always called and that only one thread and/or method is using this connection manager at a time. What could be the reason for this? Here is the initialization code I use: HttpClient httpClient = new HttpClient(); HttpClientParams httpClientParams = new HttpClientParams(); httpClient.setParams(httpClientParams); HttpConnectionManager httpConnectionManager = httpClient.getHttpConnectionManager(); httpConnectionManager.setParams(arg0) xmlRpcClient = new XmlRpcClient(); XmlRpcCommonsTransportFactory factory = new XmlRpcCommonsTransportFactory(xmlRpcClient); factory.setHttpClient(httpClient); xmlRpcClient.setTransportFactory(factory); XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); config.setServerURL(url); config.setBasicUserName(username); config.setBasicPassword(password); xmlRpcClient.setConfig(config); Thx a lot Chris
