I'm not sure, whether you have something different in mind, but the proper tools for these things are tcpmon, or wireshark.
On Mon, Nov 9, 2009 at 8:00 PM, fahad.aizaz <[email protected]> wrote: > > Hi Guys, > > The purpose I am trying to achieve is to view the XML request in the > "console" or "a file" before I use the execute method. > > For example: > The client code looks like this > > public class XmlRpc { > > XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); > > public XmlWriter > > XmlRpc() { } > > public void PrepareRequest() { > HashMap data = new HashMap(); > data.put("Type", new String("ABC") ); > data.put("Name", new String("DEF") ); > data.put("TransID", new String("987654") ); > data.put("originTimeStamp", new Date() ); > Vector params = new Vector(); > params.addElement(data); > > > XmlRpcClientConfigImpl config = new XmlRpcClientConfigImpl(); > > try { > config.setServerURL(new URL("http://192.168.0.1/owa";)); > config.setUserAgent("Gateway"); > } catch (MalformedURLException e) { > // TODO > System.err.println(e); > } > XmlRpcClient client = new XmlRpcClient(); > client.setConfig(config); > > try { > System.out.println(client.execute("TestMethod", params)); > } catch (XmlRpcException e) { > // TODO > System.err.println(e); > } > } > > } > > I would like to know if there is way that before i use the "execute" method > to sent the information to the server, what is the xml request has been > formulated. Is there anyway to see the XML request formulated and sent to > file or console or any logger. > > Your guidance would be highly appreciable. > > regards, > Fahad Aizaz > -- > View this message in context: > http://old.nabble.com/View-client-xml-request-before-execution-tp26271804p26271804.html > Sent from the Apache Xml-RPC - User mailing list archive at Nabble.com. > > -- Germanys national anthem is the most boring in the world - how telling!
