So what happens if you do the suggested toDir, but set the dir to the
same directory that you're reading from. I suspect this should work.
On 29/5/09 18:22, Lacoste, Dana (TSG Software San Diego) wrote:
Well, no: I didn't explain myself clearly J
I want to update several XML files _/in place/_ : I don't want an
"output" directory, because then I'll have to find a way to put the
files back in their original location J
so, if I do source=file.xml and dest=file.xml it overwrites the
original file with the change.
If I do source=**/file.xml without a dest= it doesn't actually do
anything.
If I do source=**/file.xml and dest=**/file.xml it doesn't do anything
(which makes sense: how can you have multiple outputs? J )
If I use <fileset> with a wildcard <include name="**/file.xml"> then
it doesn't do anything either (without the dest being set to a file,
it seems to use buffers exclusively)
I've guessed that maybe I could somehow do a <fileset> to obtain the
list and then iterate over that list with xmltask, but that seems
backwards (and I can't figure out how to make that work cleanly)
Thanks!
Dana Lacoste
*From:* Brian Agnew [mailto:br...@oopsconsultancy.com]
*Sent:* Friday, May 29, 2009 2:43 AM
*To:* Lacoste, Dana (TSG Software San Diego)
*Cc:* xmltask-users@lists.sourceforge.net
*Subject:* Re: [Xmltask-users] Using replace on multiple files?
From the manual:
<xmltask todir="output">
<fileset dir=".">
<includes name="*.xml"/>
.....
reads from the XML files in the current dir and writes to the same
filenames in the output dir.
So you need to identify the directory to write to, and it'll process
each file and write the results to the specified directory.
Brian
On 29/5/09 02:19, Lacoste, Dana (TSG Software San Diego) wrote:
So I can do this:
<xmltask source=file1.txt dest=file1.txt>
with a <replace> task and update that file's content.
Is there a way I can do this with multiple files?
i.e. when I set "source" to **/*.xml (for example) it doesn't actually
change anything if I don't set dest as well (I'm guessing it's setting
output to a buffer, which I'm not reading so I don't see any change to
the files)
(this is true if I do it as a source= or as a <fileset><include>)
Any suggestions?
Dana Lacoste
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