I want to obtain a list of all the xs:complexType @names in the xs:schema that
defines a namespace called Common. Here is a snippet of the WSDL I am trying
to parse with xmltask. It contains multiple schemas, but only the first is
shown:
<?xml version="1.0" encoding="UTF-8"?>
<wsdl:definitions
xmlns:wsdl="http://schemas.xmlsoap.org/wsdl/";
xmlns:ns0="http:asdf/Dictionary"
xmlns:ns1="http:asdf/Common"
xmlns:soap="http://schemas.xmlsoap.org/wsdl/soap/";
xmlns:tns="http://www.example.com/Services2/";
name="DictionaryService"
targetNamespace="http://www.example.com/Services2/";>
<wsdl:types>
<xs:schema
xmlns:xs="http://www.w3.org/2001/XMLSchema";
xmlns:Common="http:asdf/Common"
xmlns:ds="http:asdf/Dictionary"
attributeFormDefault="unqualified"
elementFormDefault="qualified"
targetNamespace="http:asdf/Dictionary">
<xs:import namespace="http:asdf/Common"/>
<xs:complexType name="AccountSettingsType">
<xs:sequence>
<xs:element minOccurs="0" ref="ds:UserInfo"/>
<xs:element minOccurs="0" ref="ds:Language"/>
<xs:element minOccurs="0" ref="ds:DateFormat"/>
<xs:sequence>
</xs:complexType>
...
</xs:schema
</wsdl:types>
</wsdl:definitions>
1) Using a suggestion posted by Brian Agnew a couple of years back, I can get
the first schema with this:
//*[local-name()='schema'][1]
It would be much better if I could select the schema that defines the Common
namespace (shown above.) Simply grabbing the first schema is asking for
trouble.
2) This does not return anything:
//*[local-name()='schema'][1]/*[local-name()='complexType']
What is the magic incantation?
Thanks,
Mike
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