I don't know if it is specific to Python bindings or whole lib{xml2,xslt}.
Consider simple example:
import libxml2, libxslt
doc = '''<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xbel PUBLIC "+//IDN python.org//DTD XML Bookmark Exchange Language 1.0//EN//XML" "http://pyxml.sourceforge.net/topics/dtds/xbel-1.0.dtd";>
<xbel>
</xbel>
'''
xsl = '''<?xml version="1.0" encoding="ISO-8859-2"?>
<xsl:stylesheet version="1.0"
xmlns:xsl="http://www.w3.org/1999/XSL/Transform";>
<xsl:output method="xml" indent="yes" encoding="iso-8859-2"/>
<xsl:template match='/'> <xsl:apply-templates/> </xsl:template>
<xsl:template match='/xbel'> <z/> </xsl:template>
</xsl:stylesheet> '''
xdoc = libxml2.parseDoc(doc)
print xdoc.serialize('UTF-8', 1)xxsl = libxml2.parseDoc(xsl) xxsl = libxslt.parseStylesheetDoc(xxsl) xxsl.applyStylesheet(xdoc, None)
print xdoc.serialize('UTF-8', 1)
and result:
$ python ex.py
<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE xbel PUBLIC "+//IDN python.org//DTD XML Bookmark Exchange Language 1.0//EN//XML" "http://pyxml.sourceforge.net/topics/dtds/xbel-1.0.dtd";>
<xbel version="1.0">
</xbel>
<?xml version="1.0" encoding="UTF-8"?> <xbel version="1.0"> </xbel>
It is a proper behavior? I use:
$ rpm -q libxml2 libxslt libxml2-2.6.19-1 libxslt-1.1.14-1
Regards Radek
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