On Thu, Jun 09, 2005 at 02:16:11PM -0500, John Browne wrote:
> What I have noticed is, the libxslt transformation is successful and
> works the same whether I declare the parameter using xsl:param or not.
> The following:
>
> <xsl:value-of select="$param_test"/>
>
> works fine without the xsl:param declaration, the libxslt processor
> does not give an error, and the parameter is available for use in the
> stylesheet.
>
> Shouldn't the xsl:param declaration be required and cause a
> transformation error if it's missing?
Best would be to check the spec...
http://www.w3.org/TR/xslt#top-level-variables
I would infer from 11.4 that without the declaration, the parameter
should not be in scope to the stylesheet and the reference to it should
fail. Seems you're right, please fill a bugzilla entry. It's also likely
to break existing code relying on that bug unfortunately.
Daniel
--
Daniel Veillard | Red Hat Desktop team http://redhat.com/
[EMAIL PROTECTED] | libxml GNOME XML XSLT toolkit http://xmlsoft.org/
http://veillard.com/ | Rpmfind RPM search engine http://rpmfind.net/
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