> Note that the integral is computed on deformed contour. > In <tblatex-1.png>, <tblatex-2.png> is the contact point, closer to center > than radius. Hence, dividing by a volume of the Voronoi sort would not be > consistent with the integration domain. I don't see what other volume could > be used than the one of the sphere actually (exception for Hertz-Mindlin > experts who know what is the exact very small volume change, as a function of > Poisson ratio, in the vicinity of a contact).
The volume must obviously be greater or equal to the particle-volume. A function that provide the moment tensor (\sum_k x_i^k f_j^k without division by a volume) for one particle can be used with any shape (avoid the volume computation by means of radii). It can also be summed and then divided by the volume you want... _______________________________________________ Mailing list: https://launchpad.net/~yade-dev Post to : [email protected] Unsubscribe : https://launchpad.net/~yade-dev More help : https://help.launchpad.net/ListHelp
