On 30 April 2010 07:30, Nasibeh Moradi <[email protected]> wrote:
> hi Václav, > > I attached 2 graph, compression and tension. > My law is symmetric and I have checked it. > If your law is symmetrical, what is the point to check it both in compression and tension? > it is very simple, and Kn and Ks are computed from > E and v macroscopic, so it don't need to do calibration. > I think UniaxialStrainer Engine don't work well. how do you think? you used > it before for cpm. > If it is necessary I can post my law too. > > Cheers, Nasibeh > > > > Can you post your figures? >> >> The reponse will be the same only as long as you stay in elastic domain >> (no damage, plasticity etc). Assuming your law is symmetric in the >> normal sense for tension and compression. >> >> BTW If you develop your own code and it is well separated from all other >> code, don't be afraid to have in in bzr, really. It will prevent you >> getting out of sync with then main development, we will be able to run >> scripts where your classes are used and you might receive some useful >> remarks on the code itself from others. >> >> Cheers, v. >> > > > _______________________________________________ > Mailing list: > https://launchpad.net/~yade-users<https://launchpad.net/%7Eyade-users> > Post to : [email protected] > Unsubscribe : > https://launchpad.net/~yade-users<https://launchpad.net/%7Eyade-users> > More help : https://help.launchpad.net/ListHelp > >
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