> delta_u = delta_u(real_vel) + gradVel*pos*dt; (1) >>> >>> delta_v = vel + gradVel*pos; (2) >>> >> >>> >> Heh, no! If you derive (1) vs. time, it will not give (2). >> First, divide (1) by dt to get instantaneous quantities : >> >> du/dt = vel = du_real/dt + gradVel*pos = v_real + gradvel*pos >> > Why do you say it is "instantaneous"? As I said, dt and delta_u are both incremental quantities, hence this cannot be the instantaneous velocity (which instead would be given by the derivative), it is the average of velocity in delta_t. Am I wrong?
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