Question #662105 on Yade changed: https://answers.launchpad.net/yade/+question/662105
Bruno Chareyre posted a new comment: Hi, You are right and the reason for that is that a periodic problem has no boundary, hence no boundary condition. bndCondIsPressure=[X,X,0,0,X,X] is ok but you need to impose the pressure in one internal pore to fix a reference value (arbitrary). Adding a constant pressure to a periodic pressure field still results in a valid solution. No unique solution <=> the linear system reflecting the Stokes problem is not inversible if no pressure is imposed anywhere, then crash. Bruno -- You received this question notification because your team yade-users is an answer contact for Yade. _______________________________________________ Mailing list: https://launchpad.net/~yade-users Post to : [email protected] Unsubscribe : https://launchpad.net/~yade-users More help : https://help.launchpad.net/ListHelp
