Question #688885 on Yade changed:
https://answers.launchpad.net/yade/+question/688885
mrhappy posted a new comment:
Here is my final solution:
#SET This stores all connections. 1 means intact and 0 means broken.
Connectivity = [[5000, 4900, 1],
[5001, 4901, 1],
[5002, 4902, 1],
[5003, 4903, 1],
[5004, 4904, 1],
[5005, 4905, 0],
[5006, 4906, 0],
[5007, 4907, 1],
[5008, 4908, 1],
]
#This function is called every loop to check which bond has broken
def BreakingBonds():
CurrentBonds = 0
for i in O.interactions:
CurrentBonds+=1
if Bonds0 > CurrentBonds:
global Bonds0
Bonds0 = Bonds0 - 1
print("BROKEN!")
m = 0
for row in Connectivity:
if (Connectivity[m][2] == 1):
if
(O.interactions[Connectivity[m][1],Connectivity[m][0]].phys.isBroken == True):
Connectivity[m][2] = 0
m = m + 1
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