You can't pass a directory to yara.compile(), what you can do is iterate
the directory yourself and construct a dictionary, where keys are
namespaces (you can use any string, as long as they are unique) and values
are the path to the file. Like in:
rules = yara.compile(filepaths={
'namespace1':'/my/path/rules1',
'namespace2':'/my/path/rules2'})
El 20 ene. 2018 4:54, "George Z" <[email protected]> escribió:
> hi, I'm trying to use yara.compile() to compile a large folder with
> subdirectories full of yara rules into one big rule object to run files
> against and I am trying to do this by passing the big folder to
> yara.compile() but it isn't working is there any way to do this? thanks
>
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